3.12 This exercise illustrates some anomalies of "(1). a. Define f (n) to be 0 for all n ≥ 0. Show that f is not "(1), but f is "(0). b. Define f (n) to be (n + 2)/(n + 1) for all n ≥ 0. Show that f is "(1)-and so can be said to be "constant"-even though f is not a constant function. | |
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